Re: [DL] Hey Allan a dice odds question for you

[Kirk Monsen <munchwolf@yahoo.com>]

--- Allan Seyberth <darious@darious.com> wrote:
> At 06:26 PM 5/7/00 -0400, you wrote:
> >ahhhh, but the odd do change for the higher target
> numbers, like... for
> >instance, to roll a 15 on 4d12 you need to get an
> ace and then at least
> >three, where as with 4d12+4 you only need to roll
> an 11, and that really
> >messes with the odds due to mutual exclusion and
> certain things having
> >to happen in order to have it happen.  In short,
> Aces really mess with
> >probability a lot.
> 
> So the odds of rolling a 15 on 4d12+4 are the same
> as rolling an 11 on a
> 4d12.

Likewise the odds for rolling a 15 on 4d12 and the
same odds of rolling a 19 on 4d12+4

You would need an ace and at least a 3 in both cases.

4d12 with a 12 + 3 = 15

4d12+4 with a 12 + 3 = 15, 15 + 4 = 19

There's only 12 possible results when rolling a d12,
and adding numbers only shifts what the 12 possible
results could be, yet maintains only 12 results.

-Munch Wolf

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